Chapter 7: Coordinate Geometry
Unique Previous Year Questions from the
CBSE Class 10 Basic Mathematics 2025
paper sets, covering coordinate concepts, distance formula,
section formula, midpoint, collinearity and case-study applications.
I
Multiple Choice Questions
For a point \((3,-5)\), the value of
\[
\text{abscissa}-\text{ordinate}
\]
is:
(A) \(-8\)
(B) \(-2\)
(C) \(2\)
(D) \(8\)
Set 430/1/1
2. Mid-point Ratio
1 Mark
The mid-point of a line segment divides the line segment in the ratio:
(A) \(1:2\)
(B) \(2:1\)
(C) \(1:1\)
(D) \(\frac12:2\)
Set 430/1/1
3. Coordinate Distance
1 Mark
The distance of a point \(P(3,-7)\) from the \(y\)-axis is:
(A) \(3\)
(B) \(7\)
(C) \(-7\)
(D) \(\sqrt{58}\)
Set 430/1/2
4. Literal Coordinates
1 Mark
For a point \(X(a,b)\), where \(b>a>0\), the value of
\[
[\text{distance from }x\text{-axis}]
-
[\text{distance from }y\text{-axis}]
\]
is:
(A) \(a-b\)
(B) \(b-a\)
(C) \(a^2-b^2\)
(D) \(b^2-a^2\)
Set 430/1/3
5. Distance from Origin
1 Mark
The distance of the point \((2,3)\) from the origin is:
(A) \(2\)
(B) \(3\)
(C) \(5\)
(D) \(\sqrt{13}\)
Set 430/2/1
6. Mid-point and Axis
1 Mark
The mid-point of the line segment joining the points
\((1,3)\) and \((1,-3)\) lies:
(A) at the origin
(B) in the second quadrant
(C) on \(x\)-axis
(D) on \(y\)-axis
Set 430/2/1
7. Mid-point with Variables
1 Mark
If point \((1,2)\) is the mid-point of the line segment joining
the points \((3,5)\) and \((2a,b)\), then \((a,b)=\):
(A) \((-1,-1)\)
(B) \(\left(-\frac12,-\frac12\right)\)
(C) \(\left(-\frac12,-1\right)\)
(D) \(\left(-1,-\frac12\right)\)
Set 430/3/1
8. Alternative Mid-point
1 Mark
If point \((a,2b)\) is the mid-point of the line segment joining
the points \((3,5)\) and \((-1,-1)\), then \((a,b)\) is equal to:
(A) \((1,2)\)
(B) \((2,2)\)
(C) \((2,1)\)
(D) \((1,1)\)
Set 430/3/3
9. Distance Calculation
1 Mark
The distance between the points \((2,3)\) and \((-2,-3)\) is:
(A) \(4\sqrt{13}\)
(B) \(\sqrt{40}\)
(C) \(2\sqrt{13}\)
(D) \(5\)
Set 430/5/1
The point \((x,0)\) divides the line segment joining the points
\((-4,5)\) and \((0,-10)\) in the ratio:
(A) \(1:3\)
(B) \(2:1\)
(C) \(1:1\)
(D) \(1:2\)
Set 430/5/1
11. Distance – Alternative
1 Mark
The distance between the points \((2,-7)\) and \((-2,-1)\) is:
(A) \(10\)
(B) \(2\sqrt{13}\)
(C) \(8\)
(D) \(4\sqrt{13}\)
Set 430/4/2
12. Geometric Figure Data
1 Mark
ABCD is a rectangle with its vertices at
\[
(2,-2),\;(8,4),\;(4,8),\;(-2,2)
\]
taken in order.
The length of its diagonal is:
(A) \(4\sqrt2\)
(B) \(6\sqrt2\)
(C) \(4\sqrt{26}\)
(D) \(2\sqrt{26}\)
Set 430/6/1
13. Line Equation and Point
1 Mark
The point \((3,-5)\) lies on the line
\[
mx-y=11.
\]
The value of \(m\) is:
(A) \(3\)
(B) \(-2\)
(C) \(8\)
(D) \(2\)
Set 430/6/3
II
Very Short Answer Type Questions
14. Section Formula
2 Marks
The line segment joining \((2,8)\) and \((-3,-5)\) is divided
by point \(P(x,0)\) in a fixed ratio.
Find that ratio and the value of \(x\).
Set 430/4/1
15. Trisection of a Line Segment
2 Marks
Find the coordinates of the points of trisection of the line segment
joining the points
\[
(-4,1)\quad\text{and}\quad(6,5).
\]
Set 430/5/1
Using distance formula, prove that the points
\[
(1,5),\quad(2,3),\quad(3,1)
\]
are collinear.
Set 430/5/1
17. Equidistant Relation
2 Marks
Establish a relation between \(x\) and \(y\) such that the point
\((x,y)\) is equidistant from the points
\[
(-2,5)\quad\text{and}\quad(3,9).
\]
Set 430/5/2